Published by:
CGP EDU Academic Team
Published on: August 14, 2026
How much will the reduction potential of a hydrogen electrode change when its solution initially at pH = 0 is neutralised to pH = 7 at 25ºC?
Text Solution
Verified by ExpertsThe correct answer is:
D
H + + e – ⎯→
H 2 . E = 0 –
log 10
= + 0.0591 log 10 [H + ].
E 1 = 0 {pH = 0}.
E 2 = + 0.0591log 10 [10 –7 ] = – .0591 × 7 {at pH = 7} = – 0.41 V.
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